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Timeline for Identifying a scalar function

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Feb 17, 2015 at 9:43 comment added zzz Regarding the scalar density - if you and I are thinking about the same thing I think the extra factor comes from transformation of the volume element under the same integral
Feb 17, 2015 at 9:32 comment added zzz Here we have a scalar field - maps to $\mathbb{R}$ don't pick up factors under pullbacks, e.g. see the wiki article linked above.
Feb 17, 2015 at 9:14 comment added Bence Racskó Contrast this with a so-called scalar density, which is also a scalar-valued field, but picks up the pullback's determinant as a factor, that is something that is scalar valued, but "does not transform as a scalar".
Feb 17, 2015 at 9:13 comment added Bence Racskó I question this a bit. Of course you are technically correct, but I don't think physicists call scalar fields "scalar" when they are invariant under maps. Rather this means that when you have for example a $\phi(x^1,...,x^n)$ field, then if you have some coordinate change expressible as $x^i=x^i(y^1,...y^n)$ then if you plug this directly into the field, it won't change, whereas a tensor field expressed in components would have their components changed in the usual manner.
Feb 17, 2015 at 8:21 history answered zzz CC BY-SA 3.0