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Sep 29, 2015 at 2:55 answer added CR Drost timeline score: 1
Feb 8, 2015 at 13:53 answer added Ryan Unger timeline score: 0
Feb 8, 2015 at 13:43 comment added userkls nope i know that is heat its just that we are taking the change in internal energy to be zero for an ideal gas in an isothermal process in my text
Feb 8, 2015 at 13:40 comment added Ryan Unger Are you thinking of $Q=mC_p \Delta T$?
Feb 8, 2015 at 13:39 answer added Steeven timeline score: 1
Feb 8, 2015 at 13:35 comment added userkls so change in internal energy is not a function of change in temperature then why is the change in internal energy taken to be zero in an isothermal process?
Feb 8, 2015 at 13:27 comment added Ryan Unger $dE=TdS-PdV$. I see no contradiction...
Feb 8, 2015 at 13:24 review First posts
Feb 8, 2015 at 14:17
Feb 8, 2015 at 13:22 comment added userkls i have a test 2morrow so i need the answer fast
Feb 8, 2015 at 13:21 history asked userkls CC BY-SA 3.0