Timeline for Hockey puck collision
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Feb 2, 2015 at 16:31 | comment | added | Floris | Well - you are trying to solve for $\omega$ which is obviously going to be a function of (scale linearly with) $v$ so you expect those two to be there. And the answer will depend on the radius since moment of inertia scales with radius squared but angular momentum before the collision scales with radius. The size of a puck is well known, so you can find that. I assume that the velocity is given in the question. If it is not, then express the angular velocity in terms of the initial velocity. | |
| Feb 2, 2015 at 16:28 | comment | added | user | Thanks for your detailed reply, I understand that angular momentum will be conserved, I have $mvr$ as the final and the initial angular momentum. But when I let angular momentum = $I.\omega$ then equate the two expressions for angular momentum and I am still left with $v$ and $\omega$ and $r$ in the equation. | |
| Feb 2, 2015 at 15:40 | history | answered | Floris | CC BY-SA 3.0 |