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glS
glS
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The amplitude should be proportional to the width. 

In single slit diffraction cslvulationcalculations, the resultant amplitude is goindobtained by dividing the slit width into lafge noa large number of eaualequal segments. For For each segment, the amplitude is rakentaken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. 

So amplitude should be proportional to slit width. The intesity The intensity is proportional to the square of slit width, as intensity is proportional to the square of the amplitude.

The amplitude should be proportional to the width. In single slit diffraction cslvulation, the resultant amplitude is goind by dividing the slit width into lafge no of eaual segments. For each segment, the amplitude is raken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. So amplitude should be proportional to slit width. The intesity is proportional to square of slit width, as intensity is proportional to square of amplitude.

The amplitude should be proportional to the width. 

In single slit diffraction calculations, the resultant amplitude is obtained by dividing the slit width into a large number of equal segments. For each segment, the amplitude is taken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. 

So amplitude should be proportional to slit width. The intensity is proportional to the square of slit width, as intensity is proportional to the square of the amplitude.

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R C Mishra
R C Mishra
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The amplitude should be proportional to the width. In single slit diffraction cslvulation, the resultant amplitude is goind by dividing the slit width into lafge no of eaual segments. For each segment, the amplitude is raken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. So amplitude should be proportional to slit width. Tge answer should be 5:4The intesity is proportional to square of slit width, as intensity is proportional to square of amplitude.

The amplitude should be proportional to the width. In single slit diffraction cslvulation, the resultant amplitude is goind by dividing the slit width into lafge no of eaual segments. For each segment, the amplitude is raken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. So amplitude should be proportional to slit width. Tge answer should be 5:4.

The amplitude should be proportional to the width. In single slit diffraction cslvulation, the resultant amplitude is goind by dividing the slit width into lafge no of eaual segments. For each segment, the amplitude is raken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. So amplitude should be proportional to slit width. The intesity is proportional to square of slit width, as intensity is proportional to square of amplitude.

Source Link
R C Mishra
R C Mishra
  • 71
  • 1
  • 2

The amplitude should be proportional to the width. In single slit diffraction cslvulation, the resultant amplitude is goind by dividing the slit width into lafge no of eaual segments. For each segment, the amplitude is raken proportionally equal and a constant phase difference is taken as existing between adjacent segments. The resultant amplitude is found by superposition at the point of consideration. So amplitude should be proportional to slit width. Tge answer should be 5:4.