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Kyle Kanos
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I often heard that conservation of momentum is nothing else than Newton's third law.

Ok, If you have only two interacting particles in the universe, this seems to be quite obvious.

However if you have an isolated system of $n$ ($n > 2$) interacting particles (no external forces). Then clearly Newton's third law implies conservation of total momentum of the system. However presuppose conservation of total momentum you only get:

$$ \sum_{i\neq j}^n F_{ij} = \frac{d}{d t} P = 0 $$$$ \sum_{i\neq j}^n \mathbf F_{ij} = \frac{d}{d t} \mathbf P = 0 $$

Where $F_{ij}$$\mathbf F_{ij}$ is the forced acted by the ith$i$th particle upon the jth$j$th particle and P$\mathbf P$ is the total linear momentum.

But this does'tdoesn't imply that $F_{ij} = -F_{ji}$$\mathbf F_{ij} = -\mathbf F_{ji}$ for $j \neq i$.

So does conservation of momentum implies Newton's third law in general or doesn't it? Why?

I often heard that conservation of momentum is nothing else than Newton's third law.

Ok, If you have only two interacting particles in the universe, this seems to be quite obvious.

However if you have an isolated system of $n$ ($n > 2$) interacting particles (no external forces). Then clearly Newton's third law implies conservation of total momentum of the system. However presuppose conservation of total momentum you only get:

$$ \sum_{i\neq j}^n F_{ij} = \frac{d}{d t} P = 0 $$

Where $F_{ij}$ is the forced acted by the ith particle upon the jth particle and P is the total linear momentum.

But this does't imply that $F_{ij} = -F_{ji}$ for $j \neq i$.

So does conservation of momentum implies Newton's third law in general or doesn't it? Why?

I often heard that conservation of momentum is nothing else than Newton's third law.

Ok, If you have only two interacting particles in the universe, this seems to be quite obvious.

However if you have an isolated system of $n$ ($n > 2$) interacting particles (no external forces). Then clearly Newton's third law implies conservation of total momentum of the system. However presuppose conservation of total momentum you only get:

$$ \sum_{i\neq j}^n \mathbf F_{ij} = \frac{d}{d t} \mathbf P = 0 $$

Where $\mathbf F_{ij}$ is the forced acted by the $i$th particle upon the $j$th particle and $\mathbf P$ is the total linear momentum.

But this doesn't imply that $\mathbf F_{ij} = -\mathbf F_{ji}$ for $j \neq i$.

So does conservation of momentum implies Newton's third law in general or doesn't it? Why?

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martin
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Does conservation of momentum really imply Newton's third law?

I often heard that conservation of momentum is nothing else than Newton's third law.

Ok, If you have only two interacting particles in the universe, this seems to be quite obvious.

However if you have an isolated system of $n$ ($n > 2$) interacting particles (no external forces). Then clearly Newton's third law implies conservation of total momentum of the system. However presuppose conservation of total momentum you only get:

$$ \sum_{i\neq j}^n F_{ij} = \frac{d}{d t} P = 0 $$

Where $F_{ij}$ is the forced acted by the ith particle upon the jth particle and P is the total linear momentum.

But this does't imply that $F_{ij} = -F_{ji}$ for $j \neq i$.

So does conservation of momentum implies Newton's third law in general or doesn't it? Why?