Timeline for Are the 14 Bravais lattices really distinct?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jan 21, 2015 at 6:17 | comment | added | M-J | Although it is a "special case", at the end it is a special case of "trigonal"; so it is a trigonal. How could FCC be distinct regarding this. I know FCC is a distinct form, because it has been proven mathematically by Bravais. I want an explanation apart from complicated math! | |
| Jan 20, 2015 at 14:47 | comment | added | Jon Custer | Because that 'special case' introduces new symmetries into the lattice that are not present in the trigonal case. That is the whole point - special cases are special for a mathematical reason. | |
| Jan 20, 2015 at 13:26 | comment | added | Ruslan | In the special case of $\alpha=\beta=\gamma=60^\circ$ it does have the same primitive vectors as FCC lattice, thus it coincides with it. How can their symmetries be different? | |
| Jan 20, 2015 at 13:20 | comment | added | mdib | The trigonal lattice does not have the cubic symmetry, so the fcc lattice cannot be reduced to a trigonal one. | |
| Jan 20, 2015 at 12:58 | comment | added | Ruslan | But how would you refute the claim that FCC lattice is a special case of trigonal lattice? | |
| Jan 20, 2015 at 12:28 | review | First posts | |||
| Jan 20, 2015 at 12:38 | |||||
| Jan 20, 2015 at 12:20 | history | answered | mdib | CC BY-SA 3.0 |