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Apr 6, 2022 at 20:46 comment added Shuheng Zheng How is $(m-m_0)c^2$ equal to kinetic energy? it's equal to kinetic energy plus some terms with higher orders in v
May 8, 2020 at 22:26 answer added Roghan Arun timeline score: 0
Apr 26, 2016 at 18:22 history edited Qmechanic CC BY-SA 3.0
edited tags; edited title
Jan 15, 2015 at 15:06 comment added garyp I'd go further and suggest that you purge any mention of "relativistic mass" from your brain. The concept is unnecessary and leads to confusion. It was abandoned many decades ago, but appears to persist. I'm not sure why. People must be reading old books. And perhaps writing new books based on old outdated books?
Jan 15, 2015 at 11:05 comment added user10851 Word of warning: never, never, never use the "relativistic mass" as a single symbol. Rest mass is $m$, "relativistic mass" is $\gamma m$. Hiding the $\gamma$ factor in with the $m$ is something physicists did about a century ago, before they knew any better, and it only leads to confusion.
Jan 15, 2015 at 10:33 answer added Tomas Libutti timeline score: 0
Jan 15, 2015 at 10:30 answer added Sofia timeline score: 1
Jan 15, 2015 at 10:29 answer added John Rennie timeline score: 3
Jan 15, 2015 at 10:28 history edited Sofia CC BY-SA 3.0
added 2 characters in body
Jan 15, 2015 at 10:19 history asked Shadumu CC BY-SA 3.0