Timeline for Work done: kinetic energy or area under F-ds curve?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| S Jan 2, 2015 at 8:25 | history | edited | Geoffrey | CC BY-SA 3.0 |
added latex, change tags
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| S Jan 2, 2015 at 8:25 | history | suggested | glS | CC BY-SA 3.0 |
added latex, change tags
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| Jan 2, 2015 at 7:57 | review | Suggested edits | |||
| S Jan 2, 2015 at 8:25 | |||||
| Jan 2, 2015 at 7:57 | comment | added | Guillermo Angeris | That is correct. Note that, at the point that the object is accelerating, we have some net work done in the direction of motion (that is $F\cdot ds>0$) and then the retarding force causes $F\cdot ds < 0$ by exactly the same amount, hence the change in kinetic energy is zero. | |
| Jan 2, 2015 at 7:55 | answer | added | gregsan | timeline score: 1 | |
| Jan 2, 2015 at 7:43 | review | First posts | |||
| Jan 2, 2015 at 7:58 | |||||
| Jan 2, 2015 at 7:42 | history | asked | reg | CC BY-SA 3.0 |