Skip to main content
2 events
when toggle format what by license comment
Mar 22, 2016 at 6:53 comment added user3483902 So, could a fermionic system compute a determinant of a $n$X$ n$ matrix? Since, the sign in computing the determinant of a square matrix is alternating.
Dec 27, 2014 at 11:21 history answered Phoenix87 CC BY-SA 3.0