Skip to main content
Physics

Return to Question

edited body; edited title
Source Link
glS
glS
  • 15.2k
  • 5
  • 41
  • 109

Prove the relation betweenthat relative velocity  ,momentum momentum, and energy, are related by $E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2}$

In Chapter 8 of F.Mandl's book Quantum field theoryField Theory, during the derivation of the differential cross section-section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

Prove the relation between relative velocity  ,momentum and energy

In Chapter 8 of F.Mandl's book Quantum field theory, during the derivation of the differential cross section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

Prove that relative velocity, momentum, and energy, are related by $E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2}$

In Chapter 8 of F.Mandl's book Quantum Field Theory, during the derivation of the differential cross-section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

edited body; edited tags
Source Link
Qmechanic ♦
Qmechanic ♦
  • 213.1k
  • 48
  • 590
  • 2.3k

In Chapter 8 of F.Mandl's book "Quantum field theory",Quantum field theory, during the derivation of the differential cross section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

In Chapter 8 of F.Mandl's book "Quantum field theory", during the derivation of the differential cross section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

In Chapter 8 of F.Mandl's book Quantum field theory, during the derivation of the differential cross section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

improved formatting, added tag
Source Link
edit approved Dec 17, 2014 at 13:39
glS
edit approved Dec 17, 2014 at 13:39
glS
  • 15.2k
  • 5
  • 41
  • 109

In Chapter 8 of F.Mandl's book "Quantum field theory"， I don't how to gettheory", during the relation $E_1E_2v_{rel}=[(p_1p_2)^2-m_1^2m_2^2]^{1/2}$ when derivingderivation of the differential cross section, wherethe following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses.

This may be stupid , but I'm lost in the calculation , someone please enlighten me ! How is this equation derived?

In Chapter 8 of F.Mandl's book "Quantum field theory"， I don't how to get the relation $E_1E_2v_{rel}=[(p_1p_2)^2-m_1^2m_2^2]^{1/2}$ when deriving the differential cross section, where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses.

This may be stupid , but I'm lost in the calculation , someone please enlighten me !

In Chapter 8 of F.Mandl's book "Quantum field theory", during the derivation of the differential cross section, the following relation is used: $$E_1E_2v_{rel}=\sqrt{(p_1p_2)^2-m_1^2m_2^2} \,\, ,$$ where $v_{rel}$ is the relative velocity between two colliding particles, $m_1$ and $m_2$ are the rest masses. How is this equation derived?

Source Link
Simon
Simon
  • 362
  • 2
  • 10