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Sep 21, 2011 at 14:14 comment added dmckee --- ex-moderator kitten @Richard, well I was a JLAB medium-energy, hard-probe kind of nuclear physicist rather than a xray-spectrum, energy-level-forest, multipole-transition listing kind of nuclear physicist. So I have broad regions of ignorance in what would have been a traditional nuclear physicist core competency.
Sep 21, 2011 at 13:51 vote accept Chris B. Behrens
Sep 21, 2011 at 4:20 comment added Richard Terrett dmckee - your deduction is spot on. I find it interesting that you've not encountered this term - Technetium-99m (used as a medical tracer) is a fairly well known 'nuclear isomer'. Perhaps there are other names used for these states?
Sep 20, 2011 at 20:45 comment added Chris B. Behrens Ah...that's useful. Sounds like I have some more reading to do.
Sep 20, 2011 at 20:43 comment added dmckee --- ex-moderator kitten If this conjecture is correct, yes a rearranging of the nucleons (how familiar are you with the nuclear shell model?). However, the potential released will be primarily related to the strong nuclear force (as manifested at nuclear lengths scales i.e. meson exchange potentials).
Sep 20, 2011 at 20:39 comment added Chris B. Behrens So basically, it's neutrons and protons in a less stable configuration. And when the nucleus collapses to a more stable configuration, it's releasing the previously potential weak nuclear force?
Sep 20, 2011 at 19:15 history answered dmckee --- ex-moderator kitten CC BY-SA 3.0