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Nov 24, 2014 at 0:33 comment added KSab @JoshuaBenabou Your point is a valid one, static friction is the type of friction you are talking about, which basically perfectly counteracts any forces working parallel to the ground, however in the case above, where the only force present is a normal force perfectly perpendicular to the ground, friction is still 0. My point was that in the scenario friction is 0 and a non-factor.
Nov 24, 2014 at 0:13 comment added math_lover Also this is question about vectors.
Nov 23, 2014 at 23:59 comment added math_lover Sorry, you are wrong. Consider two books, stacked on top of eachother with friction acting between them. The lower book rests on a frictionless surface. You pull the lower book with some force $F$, and if $F$ is sufficiently small, friction from the lower book acting on the top book will pull the top book so that the top book remains stationary above the lower book. Thus you may have 0 velocity with resepct to the station, but friction can also be acting on you.
Nov 23, 2014 at 21:25 review First posts
Nov 23, 2014 at 21:31
Nov 23, 2014 at 21:15 history answered KSab CC BY-SA 3.0