Timeline for How does a single charge produce magnetic field?
Current License: CC BY-SA 3.0
11 events
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| Apr 13, 2017 at 12:39 | history | edited | CommunityBot |
replaced http://physics.stackexchange.com/ with https://physics.stackexchange.com/
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| Nov 9, 2014 at 17:39 | history | edited | Nikos M. | CC BY-SA 3.0 |
added 80 characters in body
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| Nov 9, 2014 at 17:37 | comment | added | Nikos M. | @AlfredCentauri, yes it is an overloading of notation (where $Q$ means charge density), fixing that! | |
| Nov 9, 2014 at 17:35 | comment | added | Alfred Centauri | Nikos, yes $\vec j$ is current density which is why I'm puzzled. Current density is in ampere's per square meter but $q\vec v$ has unit ampere meter. I suspect you meant to write something like $\vec j = \rho(\mathbf r) \vec v$ where the charge density is a delta function for a point charge. | |
| Nov 9, 2014 at 17:30 | history | edited | Nikos M. | CC BY-SA 3.0 |
added 20 characters in body
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| Nov 9, 2014 at 17:28 | comment | added | Nikos M. | @AlfredCentauri, for example take a look at this lecture, eq for B under current density and equation for B under Magnetic Field of a Moving Charge (current density is $\vec{j}=q\vec{v}$) it is current density actually (that is why slightly differnt symbol) | |
| Nov 9, 2014 at 17:25 | comment | added | Nikos M. | @AlfredCentauri, yes it is not exact actually (i'll have to look it up, dont remember exact form), but the equation states how a current is generated (or equivalent) to a moving charge | |
| S Nov 9, 2014 at 17:23 | history | suggested | bot47 | CC BY-SA 3.0 |
Less ugly.
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| Nov 9, 2014 at 17:17 | comment | added | Alfred Centauri | Nikos, your first equation is puzzling to me. | |
| Nov 9, 2014 at 17:11 | review | Suggested edits | |||
| S Nov 9, 2014 at 17:23 | |||||
| Nov 9, 2014 at 15:27 | history | answered | Nikos M. | CC BY-SA 3.0 |