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# Does voltage drop occursoccur with zero load and zero resistance

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1. Imagine a circuit consisting of just a battery and conducting wires which have zero dissipativity so that there is no loss of energy( Zero resistance). If the wires are connected to both terminals the current will flow in the direction of lower potential. Can we say that there has been a voltage drop in the current in going from positive terminal to negative terminal? I asked this question because voltage drop happens across resistor and I don't understand why it should occur only there. Because I think, considering a positive test charge its electric potential should decrease as it travel from higher potential to lower potential immaterial of whether any dissipation occurs or not.Does voltage drop refers to loss in total energy of electron i.e. because in this case KE + Electric potential will be zero and the total energy of electrons remains unchanged.

Imagine a circuit consisting of just a battery and conducting wires which have zero dissipativity so that there is no loss of energy( Zero resistance). If the wires are connected to both terminals the current will flow in the direction of lower potential. Can we say that there has been a voltage drop in the current in going from positive terminal to negative terminal? I asked this question because voltage drop happens across resistor and I don't understand why it should occur only there. Because I think, considering a positive test charge its electric potential should decrease as it travel from higher potential to lower potential whether any dissipation occurs or not.Does voltage drop refers to loss in total energy of electron i.e. because in this case KE + Electric potential will be zero and the total energy of electrons remains unchanged and thus we can says that voltage drop is zero.
2. Is voltage drop(assumed here to mean loss in electric potential) equal to work output under normal conditions. I think no - because electric potential difference gets converted into kinetic energy of electrons out of which only some gets converted into heat or is it the case that in
a resistor entire kinetic energy gets converted into another energy such as heat?

Is voltage drop(assumed here to mean loss in electric potential) equal to work output under normal conditions. I think no - because electric potential difference gets converted into kinetic energy of electrons out of which only some gets converted into heat or is it the case that in
a resistor entire kinetic energy gets converted into another energy such as heat?
3. Is electric field inside circuit constant? If yes how? Will not the shape of circuit matter?
1. Imagine a circuit consisting of just a battery and conducting wires which have zero dissipativity so that there is no loss of energy( Zero resistance). If the wires are connected to both terminals the current will flow in the direction of lower potential. Can we say that there has been a voltage drop in the current in going from positive terminal to negative terminal? I asked this question because voltage drop happens across resistor and I don't understand why it should occur only there. Because I think, considering a positive test charge its electric potential should decrease as it travel from higher potential to lower potential immaterial of whether any dissipation occurs or not.Does voltage drop refers to loss in total energy of electron i.e. because in this case KE + Electric potential will be zero and the total energy of electrons remains unchanged.

2. Is voltage drop(assumed here to mean loss in electric potential) equal to work output under normal conditions. I think no - because electric potential difference gets converted into kinetic energy of electrons out of which only some gets converted into heat or is it the case that in
a resistor entire kinetic energy gets converted into another energy such as heat?

3. Is electric field inside circuit constant? If yes how? Will not the shape of circuit matter?
1. Imagine a circuit consisting of just a battery and conducting wires which have zero dissipativity so that there is no loss of energy( Zero resistance). If the wires are connected to both terminals the current will flow in the direction of lower potential. Can we say that there has been a voltage drop in the current in going from positive terminal to negative terminal? I asked this question because voltage drop happens across resistor and I don't understand why it should occur only there. Because I think, considering a positive test charge its electric potential should decrease as it travel from higher potential to lower potential whether any dissipation occurs or not.Does voltage drop refers to loss in total energy of electron i.e. because in this case KE + Electric potential will be zero and the total energy of electrons remains unchanged and thus we can says that voltage drop is zero.
2. Is voltage drop(assumed here to mean loss in electric potential) equal to work output under normal conditions. I think no - because electric potential difference gets converted into kinetic energy of electrons out of which only some gets converted into heat or is it the case that in
a resistor entire kinetic energy gets converted into another energy such as heat?
3. Is electric field inside circuit constant? If yes how? Will not the shape of circuit matter?
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# Does voltage drop occurs with zero load and zero resistance

1. Imagine a circuit consisting of just a battery and conducting wires which have zero dissipativity so that there is no loss of energy( Zero resistance). If the wires are connected to both terminals the current will flow in the direction of lower potential. Can we say that there has been a voltage drop in the current in going from positive terminal to negative terminal? I asked this question because voltage drop happens across resistor and I don't understand why it should occur only there. Because I think, considering a positive test charge its electric potential should decrease as it travel from higher potential to lower potential immaterial of whether any dissipation occurs or not.Does voltage drop refers to loss in total energy of electron i.e. because in this case KE + Electric potential will be zero and the total energy of electrons remains unchanged.

2. Is voltage drop(assumed here to mean loss in electric potential) equal to work output under normal conditions. I think no - because electric potential difference gets converted into kinetic energy of electrons out of which only some gets converted into heat or is it the case that in
a resistor entire kinetic energy gets converted into another energy such as heat?

3. Is electric field inside circuit constant? If yes how? Will not the shape of circuit matter?