Timeline for What is the commutator of an operator and its derivative?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 21, 2019 at 2:11 | comment | added | Ivan Burbano | The last commutator you wrote vanishes identically. However, it doesn't help to solve $[\partial_x O(x),O(x)]\neq\partial_x[O(x),O(x)]$. In particular, there is no reason why $[\partial_x O(x),O(x)]$ vanishes in general. Rather, One should evaluate $[\partial_x O(x),O(x')]$ in the fashion you showed and then evaluate at $x'=x$. | |
| Nov 23, 2017 at 1:35 | comment | added | Drake Marquis | @Soap Hi, if they are the same, the commutator vanishes identically. This is consistent with what I wrote. | |
| Nov 22, 2017 at 17:02 | comment | added | soap | but $x$ may be equal to $x'$ | |
| Oct 17, 2014 at 17:28 | history | answered | Drake Marquis | CC BY-SA 3.0 |