Timeline for Where does de Broglie wavelength $\lambda=h/p$ for massive particles come from?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Oct 10, 2014 at 12:01 | comment | added | Ruslan | Shouldn't $\vec k$ incorporate the $2\pi$ factor in your formula? | |
| Oct 10, 2014 at 10:22 | comment | added | gatsu | I guess that the argument consists in substance to realize that both $\vec{k}$ (from the shape of its contribution to the phase) and $\vec{p}$ (because it is the generator of the Lie spacial translation group) perform a translation of the system by a vector $\vec{x}$; thus they have to be proportional. I am not sure, invoking special relativity is necessary here, or at least I wonder whether it is really necessary. | |
| Oct 10, 2014 at 10:15 | vote | accept | Muster Mark | ||
| Oct 10, 2014 at 10:09 | history | answered | Danu | CC BY-SA 3.0 |