Timeline for Why particle number operator $\hat{N}$ is $\hat{a}^\dagger\hat{a}$ rather than $\hat{a}\hat{a}^\dagger$?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 12, 2014 at 7:15 | comment | added | suresh | @PranavHosangadi Explanation added. I hope that suffices. | |
| Oct 12, 2014 at 7:15 | history | edited | suresh | CC BY-SA 3.0 |
explanation added
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| Oct 10, 2014 at 23:50 | comment | added | Jold | I think he means that $a^\dagger a$ kills the vacuum while $a \, a^\dagger$ doesn't. | |
| Oct 10, 2014 at 8:05 | comment | added | pho | You want to elaborate on this a bit? | |
| Oct 10, 2014 at 7:27 | review | Low quality answers | |||
| Oct 10, 2014 at 8:05 | |||||
| Oct 10, 2014 at 7:11 | history | answered | suresh | CC BY-SA 3.0 |