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Sep 30, 2014 at 15:21 comment added StephenJ Yes, that is correct. Kinetic energy and position do not obey the same kind of uncertainty relation that position and momentum do. I wouldn't say that df/dx necessarily has direct physical significance, but if f is the wavefunction then -i hbar df/dx is the momentum.
Sep 30, 2014 at 4:18 comment added Coburn Just to clarify, so is there no "uncertainty principle" for kinetic energy and position like the way position and momentum do? Also, I'm wondering what is the physical meaning/significance of df/dx?
Sep 29, 2014 at 21:05 history answered StephenJ CC BY-SA 3.0