Timeline for Why work $W$ and heat $Q$ are different concepts?
Current License: CC BY-SA 3.0
6 events
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Mar 10, 2017 at 8:56 | comment | added | Jonas Greitemann | @DSuchet You're absolutely right of course. I changed that. In terms of differentials, I've seen $\mathrm d U=\delta Q + \delta W$ where $\delta$ indicates an inexact differential. Put simply, they are 'infinitesimal' amounts of heat and work but they cannot be integrated to give a path-independent state function. | |
Mar 10, 2017 at 8:51 | history | edited | Jonas Greitemann | CC BY-SA 3.0 |
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Mar 10, 2017 at 7:40 | comment | added | Pen | About notations : I avoid $\Delta W$ and $\Delta Q$ as transferred work and heat may not be differential forms | |
Sep 15, 2014 at 8:29 | history | edited | Jonas Greitemann | CC BY-SA 3.0 |
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Sep 14, 2014 at 23:53 | history | edited | Jonas Greitemann | CC BY-SA 3.0 |
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Sep 14, 2014 at 23:44 | history | answered | Jonas Greitemann | CC BY-SA 3.0 |