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Sep 14, 2014 at 15:17 history edited Alfred Centauri CC BY-SA 3.0
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Sep 14, 2014 at 15:00 comment added Jessica Hansen (2) the physical (normalizable) unbound states are not eigenstates of the Hamiltonian, i.e., the physical unbound states are not states of definite energy but are, instead, a distribution of energy eigenstates, e.g., a wavepacket. That was the crucial misunderstanding on my part. I had (incorrectly) understood that the wave function of a free particle was non-normalizable in general, not just for particular energy states.
Sep 14, 2014 at 14:58 vote accept Jessica Hansen
Sep 14, 2014 at 14:55 vote accept Jessica Hansen
Sep 14, 2014 at 14:55
Sep 14, 2014 at 14:45 history answered Alfred Centauri CC BY-SA 3.0