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Timeline for Asymptotic freedom in QCD

Current License: CC BY-SA 3.0

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Sep 14, 2014 at 19:45 vote accept CommunityBot
Sep 14, 2014 at 8:55 comment added Orbifold Yes you are right. I should have mentioned that both the expressions are correct modulo a numerical factor that can be absorbed in the constant 'a'. This can always be done by the redefinition of the coupling. Thanks for pointing out.
Sep 14, 2014 at 8:39 comment added Andrew McAddams No, expression $\beta (g) = ag^{2}$ is right.
Sep 14, 2014 at 8:23 history answered Orbifold CC BY-SA 3.0