Timeline for Is it true that any system of accelerating charges will radiate?
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Mar 1, 2021 at 0:54 | comment | added | John McAndrew | @ahemmetter the EM radiation from and radiation reaction force on each element of a ring of constant current is exactly cancelled by that from the EM radiation from all other elements of the ring. You will never exactly get this with equispaced discrete charges circulating in a ring, although it will approach it as you increase the number of discrete charges. | |
| Apr 2, 2019 at 8:48 | comment | added | DK2AX | @StanLiou Charges in a storage ring of a particle accelerator constitute a (constant, I assume) circular current and do radiate - this is often even their primary purpose (e.g. PETRA III). What is the fundamental difference between a ring carrying a constant current and electrons being being kept on a circular beam path? | |
| Aug 5, 2016 at 19:11 | comment | added | Bill Alsept | @StanLiou if you keep the current constant then there is no acceleration. So of course there would not be radiation. | |
| Aug 15, 2011 at 18:15 | comment | added | Stan Liou | If you keep the charge density and current constant, there cannot be radiation, whether in the context of non-relativistic electrodynamics or fully covariant Maxwell's equations. I'll edit in some details, which might also address Vladimir (not entirely sure what he's referring to). | |
| Aug 15, 2011 at 4:57 | comment | added | endolith | So a ring of electrons traveling in a loop at relativistic speeds will not radiate? | |
| Aug 12, 2011 at 19:31 | comment | added | Vladimir Kalitvianski | I confuse nothing. | |
| Aug 12, 2011 at 19:25 | comment | added | Stan Liou | You're confusing accelerating the superconductor and accelerating the charge within it. | |
| Aug 12, 2011 at 19:10 | comment | added | Vladimir Kalitvianski | A stationary ring, superconducting or not, can be of any shape but a rotating one must be ideal. | |
| Aug 12, 2011 at 19:04 | comment | added | Stan Liou | A superconducting ring doesn't need to be ideally-shaped to carry a persistent current. The end result is still rotating charge with no cyclotron-type radiation. | |
| Aug 12, 2011 at 17:24 | comment | added | Vladimir Kalitvianski | You mean rotation around the ring axis perpendicular to the ring plane. It's true but for not radiating the charge must be uniformly distributed and the ring must be ideal in shape. | |
| Aug 12, 2011 at 3:25 | history | edited | Stan Liou | CC BY-SA 3.0 |
added 67 characters in body
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| Aug 12, 2011 at 3:23 | vote | accept | a06e | ||
| Aug 12, 2011 at 3:18 | history | answered | Stan Liou | CC BY-SA 3.0 |