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Aug 30, 2014 at 23:43 vote accept Fraïssé
Aug 29, 2014 at 5:00 history tweeted twitter.com/#!/StackPhysics/status/505218421580394496
Aug 29, 2014 at 2:56 comment added Brian Bi I only use $\wedge$ for $\times$ when I'm writing by hand, to avoid confusing $\times$ with $x$. But to be precise, wedge and cross products truly are distinct operations. One gives you a rank-2 tensor, the other a pseudovector.
Aug 29, 2014 at 2:40 answer added alemi timeline score: 12
Aug 29, 2014 at 2:24 answer added Muphrid timeline score: 14
Aug 29, 2014 at 2:01 comment added Kyle Kanos AFAIK, in 3D, $\wedge\equiv\times$.
Aug 29, 2014 at 1:55 history asked Fraïssé CC BY-SA 3.0