Timeline for Any ket as a sum of eigenkets of a given observable
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Aug 21, 2014 at 9:44 | vote | accept | TheJerseyChemist | ||
| Aug 21, 2014 at 9:25 | comment | added | Valter Moretti | @Danu I am in chat... | |
| Aug 21, 2014 at 9:24 | comment | added | TheJerseyChemist | Both excellent answers by the way. To further clarify, does that mean when we actually measure an observable of a general state, then we're only interested in one dimension of this Hilbert space? Or to attempt geometric intuition: analogous to moving along a single axis in the Cartesian plane (but clearly in higher dimensions)? | |
| Aug 21, 2014 at 9:22 | comment | added | Danu | @ValterMoretti by the way, could I talk to you in chat for a minute? I'm about to start a math. phys. degree and am looking for some advice! | |
| Aug 21, 2014 at 9:20 | comment | added | Danu | @ValterMoretti covers the mathematical idea (as does Ignacio's answer). I tried to address the physical picture with my answer. | |
| Aug 21, 2014 at 9:19 | answer | added | Ignacio Vergara Kausel | timeline score: 2 | |
| Aug 21, 2014 at 9:18 | comment | added | Valter Moretti | "kets" are nothing but vectors in a Hilbert space. Every vector can always be decomposed along a Hilbert basis. Every observable with (pure point spectrum) has a Hilbert basis of eigenvectors. Thus: Every vector ("ket") can be written as a (generally infinite) sum of eigenvectors of any independently given observable (with pure point spectrum). | |
| Aug 21, 2014 at 9:18 | answer | added | Danu | timeline score: 3 | |
| Aug 21, 2014 at 9:13 | history | edited | TheJerseyChemist | CC BY-SA 3.0 |
added 216 characters in body
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| Aug 21, 2014 at 9:06 | history | asked | TheJerseyChemist | CC BY-SA 3.0 |