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Bernhard
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Time Dilation = 1/squareroot of 1-v^2/c^2$1/\sqrt{ 1-v^2/c^2}$ but why? How do you get to that conclusion? I know you use Pythagoras'theorem and my current understand goes like this:

vt^2+ct^2=cT^2$$vt^2+ct^2=cT^2$$

then you take the square root of Ct^2$Ct^2$ and from there I think you divide by c$c$ to get the time dilation but I'm not sure. And if this is correct what steps do you take to get to the formula used now

Time Dilation = 1/squareroot of 1-v^2/c^2 but why? How do you get to that conclusion? I know you use Pythagoras'theorem and my current understand goes like this:

vt^2+ct^2=cT^2

then you take the square root of Ct^2 and from there I think you divide by c to get the time dilation but I'm not sure. And if this is correct what steps do you take to get to the formula used now

Time Dilation = $1/\sqrt{ 1-v^2/c^2}$ but why? How do you get to that conclusion? I know you use Pythagoras'theorem and my current understand goes like this:

$$vt^2+ct^2=cT^2$$

then you take the square root of $Ct^2$ and from there I think you divide by $c$ to get the time dilation but I'm not sure. And if this is correct what steps do you take to get to the formula used now

added 328 characters in body; edited tags; edited title
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Ray Kay
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Time Dilation = 1/squareroot of 1-v^2/c^2 but why? How do you get to that conclusion? I know that time dilationyou use Pythagoras'theorem and length contraction are "governed"my current understand goes like this:

vt^2+ct^2=cT^2

then you take the square root of Ct^2 and from there I think you divide by c to get the Lorentz factor $$\gamma=\left(\sqrt{1-\frac{v^2}{c^2}}\right)^{-1}$$ But whattime dilation but I'm not sure. And if this is correct what steps do you take to get to the intuition behind this (strange-looking) expressionformula used now

I know that time dilation and length contraction are "governed" by the Lorentz factor $$\gamma=\left(\sqrt{1-\frac{v^2}{c^2}}\right)^{-1}$$ But what is the intuition behind this (strange-looking) expression

Time Dilation = 1/squareroot of 1-v^2/c^2 but why? How do you get to that conclusion? I know you use Pythagoras'theorem and my current understand goes like this:

vt^2+ct^2=cT^2

then you take the square root of Ct^2 and from there I think you divide by c to get the time dilation but I'm not sure. And if this is correct what steps do you take to get to the formula used now

added 155 characters in body; edited tags; edited title
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Danu
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What is the logicintuition behind the formula for special relativity?Lorentz factor from Special Relativity

Time Dilations = 1/squareroot of 1I know that time dilation and length contraction are "governed" by the Lorentz factor $$\gamma=\left(\sqrt{1-\frac{v^2}{c^2}}\right)^{-1}$$ But what is the intuition behind this (strange-v^2/c^2 but why?looking) expression

What is the logic behind the formula for special relativity?

Time Dilations = 1/squareroot of 1-v^2/c^2 but why?

What is the intuition behind the Lorentz factor from Special Relativity

I know that time dilation and length contraction are "governed" by the Lorentz factor $$\gamma=\left(\sqrt{1-\frac{v^2}{c^2}}\right)^{-1}$$ But what is the intuition behind this (strange-looking) expression

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Ray Kay
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