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You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$$S=k_B\ln\Omega$. Then the S under other temperature should be $S=\int_0^T{dQ/T}$$S=\int_0^T{\frac{dQ}{T}}$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$. Then the S under other temperature should be $S=\int_0^T{dQ/T}$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_B\ln\Omega$. Then the S under other temperature should be $S=\int_0^T{\frac{dQ}{T}}$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$. Then the S under other temperature should be $S=\int_0^T{Q/T}dT$$S=\int_0^T{dQ/T}$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$. Then the S under other temperature should be $S=\int_0^T{Q/T}dT$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$. Then the S under other temperature should be $S=\int_0^T{dQ/T}$.
You can set the entropy of your system under zero temperature to zero in compliance with the statistical definition $S=k_Bln\Omega$. Then the S under other temperature should be $S=\int_0^T{Q/T}dT$.
