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Aug 12, 2014 at 1:12 history edited argonaut CC BY-SA 3.0
Removed unnecessary equations and tried to improve meaning of my question
Aug 10, 2014 at 4:41 comment added argonaut Thanks for the extra information. Simply, I want to confirm if we just use $$f_1 = 1/\sqrt{1 - β^2}$$ for the frequency received in the rotating frame, and then just finding the reciprocal for the frequency received in the central frame
Aug 9, 2014 at 15:37 comment added user4552 You don't need to use the Schwarzschild metric for this. You could simplify the calculation a lot by just using $g_{tt}=e^{2\Phi}$, where $\Phi=-GM/r$. If you want to do a numerical check on your result using data for a GPS satellite, you can check it against my calculation here lightandmatter.com/genrel , ch. 2, example 12.
Aug 9, 2014 at 14:27 history asked argonaut CC BY-SA 3.0