Timeline for Describing a circular current loop as delta functions
Current License: CC BY-SA 3.0
3 events
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Jul 30, 2014 at 16:26 | comment | added | Ben | I don't think this is correct because the $\sin\theta$ should be $\sin\pi/2$. See edit | |
Jul 30, 2014 at 13:52 | comment | added | Ultima | I just want to note that, as I mention in my post, the sine term is completely superfluous. If it weren't, however, there would be no mathematical justification in including it. Your formula should be sin(root), which is 1, not sin(theta). | |
Jul 30, 2014 at 13:44 | history | answered | yankeefan11 | CC BY-SA 3.0 |