Timeline for Differences between wavefunction, probability and probability density?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 17, 2019 at 19:43 | comment | added | Antonios Sarikas | Isn't $P(r)4πr^2$ the radial probability distribution (probability per radius)? So the maximum we get in Bohr radius is the probability density and not the probability, right? Thanks in advance. | |
| Sep 17, 2019 at 16:30 | comment | added | John Rennie | @adosar remember that ${\bf P} = PdV$. If the particle is at a distance from $r$ to $r+dr$ from the nucleus that means it is in a spherical shell of radius $r$ and thickness $dr$. The volume of this shell is $dV = 4\pi r^2 dr$. So the probability of finding the particle at a distance $r$ is ${\bf P}(r) = P(r) 4\pi r^2$. It's that extra factor of $r^2$ that produces the maximum at the Bohr radius. | |
| Sep 17, 2019 at 15:57 | comment | added | Antonios Sarikas | Why the probability is maximum for the hydrogen atom for the electron to be at Bohr radius whereas the is the probability density that is maximum and not the probabilty? Could we say that $dp=Pdx$ is maximum in the radius where probability density is maximum? "P" stands for probability density. | |
| Jul 20, 2014 at 6:55 | history | answered | John Rennie | CC BY-SA 3.0 |