in order to confirm whether I understand the relation ship between amps, columbs and electrons I decided to try out the following.
my laptop adapter's label reads 3.34 amps. I assume that:
- amps are the rate of flow of charge (i.e speed of flow measured in coulombs per second) at a point in a circuit.
- that elementary charge (e) is the charge of one electron
- that one coulomb is the sum of the charge given by 1/e electrons
so the number of electrons that will pass through my laptop (or at least the adapter) per second are:
3.34 x (1/e) = 2.084664255E19 electrons
is this correct?
EDIT: having seen the answers I have seen that there's a lot of information missing here.
The point of the circuit I would like to focus on is any cross section of the cable that leads from the adapter to the laptop.
I also assume that the laptop is at full power and drawing the following as labelled on the adapter:
- 19.5 V (since this is out of the adapter I'm assuming DC current)
- 3.34 A