Timeline for Divergence of a field and its interpretation
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Jul 14, 2014 at 9:27 | comment | added | ticster | @Subhra No you could not, nor could you find the integral equivalent. While an $\vec{E}$ field would be generated, any closed surface integral of it would be null. | |
| Jul 14, 2014 at 5:59 | comment | added | Subhra | @ticster: I fully agree with your last sentence and I realized it at the very beginning of my study of electricity and magnetism. If you are allowed to generate electric field only from magnetic flux can a non zero divergence of electric field be found anyway? | |
| Jul 13, 2014 at 22:48 | comment | added | ticster | +1 because the key point is that what we measure is the integral form of Maxwell's laws. You should probably remove the part that says $\rho \rightarrow \inf$. Even though it links back with the divergences he brought up I think it's just confusing Subhra. What he needs to understand is that is that if we ever measure a non zero integral of $d^2 \vec{S} . \vec{B}$ over a closed surface, we will admit the existence of magnetic monopoles, so there is no double standard. | |
| Jul 13, 2014 at 20:04 | comment | added | By Symmetry | The divergence is a function of position. I haven't been terribly clear and have used $V$ to mean both the set of points being integrated over and the volume of that set of points. I hope its clear from the context which is meant. (Hey this is Physics SE not Math SE) Clearly if I consider $\nabla\cdot\vec{E}$ if two different regions of space it will, in general, be different. | |
| Jul 13, 2014 at 19:56 | comment | added | Subhra | So the divergence depends on the choice of V. | |
| Jul 13, 2014 at 19:23 | history | answered | By Symmetry | CC BY-SA 3.0 |