Timeline for Why doesn't a typical beam splitter cause a photon to decohere?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 24, 2020 at 17:20 | comment | added | Árpád Szendrei | Really nice answer. | |
| Jun 25, 2014 at 13:33 | history | edited | anna v | CC BY-SA 3.0 |
had misunderstood set up
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| Jun 25, 2014 at 13:14 | comment | added | anna v | @PeterShor OK, I misunderstood the problem. I will edit, since the interference is between the through going and the reflected. | |
| Jun 25, 2014 at 13:12 | comment | added | anna v | @PeterShor The problem as set up by the OP gives 50% reflection. | |
| Jun 25, 2014 at 13:06 | comment | added | Peter Shor | None of the photons are absorbed (or rather, since the apparatus isn't perfect, a very small fraction; much less than 50%). | |
| Jun 25, 2014 at 13:02 | comment | added | anna v | @PeterShor I am talking of the 50% per mirror inelastic, absorbed photons. Their energy is transfered to the solid state in various ways. | |
| Jun 25, 2014 at 12:23 | comment | added | Peter Shor | There's no heat transferred ... the photon has the same energy after it passes through the mirror as before. | |
| Jun 25, 2014 at 11:05 | history | answered | anna v | CC BY-SA 3.0 |