Timeline for Moon's pull causes tides on far side of Earth: why?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Jun 11, 2014 at 10:27 | comment | added | Marc van Leeuwen | Also the center of gravity of the Earth-Moon system is actually inside the Earth's surface. | |
| Jun 9, 2014 at 15:18 | comment | added | dmckee --- ex-moderator kitten | Tides can be coherently explained in terms of orbital dynamics (this is the method preferred by most SF writers), but it has to be done carefully and not in terms of centripetal forces or centrifugal pseudo-forces. | |
| Jun 9, 2014 at 15:14 | comment | added | Marc van Leeuwen | No, this is incorrect. Tidal forces are due to the differential of the gravitational field one object exerts on the other. Two equal mass objects orbiting around each other would exert qualitatively the same kind of tidal force fields (double bulge) upon each other as does the Moon on the Earth, even though in that case they would both be circling a centre-of-mass in the middle, with all "centrifugal forces" directed away from this point. | |
| Jun 9, 2014 at 15:13 | review | First posts | |||
| Jun 9, 2014 at 15:14 | |||||
| Jun 9, 2014 at 14:54 | history | answered | Roger | CC BY-SA 3.0 |