Timeline for quick question about degeneracy
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 8, 2014 at 19:43 | vote | accept | user44840 | ||
| Jun 8, 2014 at 19:27 | answer | added | Edwin_R | timeline score: 2 | |
| Jun 8, 2014 at 19:24 | history | edited | user44840 | CC BY-SA 3.0 |
added 37 characters in body
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| Jun 8, 2014 at 19:24 | comment | added | user44840 | that's what I got as well. Since the energy is given by $E_n = E_{n1} + E_{n2} = (1 + n_1 + n_2)\hbar \omega $, is the degeneracy 2? This question is about two non-interacting particles in a potential well. | |
| Jun 8, 2014 at 19:01 | comment | added | Count Iblis | The state of two identical spinless particles must be symmetric w.r.t. permutations. So, the first excited state must be 1/sqrt(2) [|1,0> + |0,1>]. Interchaning the two particles does not yield a different state. | |
| Jun 8, 2014 at 17:20 | history | asked | user44840 | CC BY-SA 3.0 |