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Apr 13, 2017 at 12:57 history edited CommunityBot
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Jun 7, 2014 at 17:10 history edited Qmechanic CC BY-SA 3.0
Added explanation
Jun 6, 2014 at 16:31 comment added user7757 Thanks for your answer. The point I am trying to take is the holomorphic and the anti-holomorphic sectors are identical in every aspect, so I am puzzled how working with just one variable gives you the whole answer. Just replace $z$ by $\bar{z}$ and $h$ by $\bar{h}$. I am trying to think of this as writing a coupled system in 2D into normal modes, but the two normal modes are physically distinguishable, but here there is no such thing, as the hilbert spaces seem to be isomorphic.
Jun 6, 2014 at 16:18 history edited Qmechanic CC BY-SA 3.0
Added explanation
Jun 5, 2014 at 15:25 history answered Qmechanic CC BY-SA 3.0