Timeline for Signal Induction in a Wire due to Alternating Current
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 30, 2014 at 17:51 | vote | accept | Martin Marinov | ||
| May 30, 2014 at 17:44 | comment | added | WalyKu | You can for a detailed analysis use power line models. These incorporate segmentation into 4-pole $\Pi$ elements. That way the mutual elements(inductance, capacitance) will be in every $\Pi$ element, where every of these elements represents a defined length. The other thing you could consider is wave propagation equations(mentioned at the end). That would probably be an overkill, but it would surely be interesting. | |
| May 30, 2014 at 17:34 | comment | added | WalyKu | Perfect coupling means that absolutely everything from the first wire is coupled to the second wire. Think of a transformer as a 4 pole element. When it is perfect you simply connect the terminals as if there was absolutely no resistance/inductance whatever. So yes the amplitudes will be the same as they will practically be connected to each other on each end($-\infty$ and $+\infty$). It's a really ridiculous oversimplified case. | |
| May 30, 2014 at 17:27 | comment | added | Martin Marinov | So in the perfect case where $\phi = 0$, do I expect to see the same amplitude in wire B, namely will $\hat{A} = A$ ? Does the distance between the wire change anything? | |
| May 30, 2014 at 16:28 | history | answered | WalyKu | CC BY-SA 3.0 |