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Oct 2, 2016 at 18:07 history edited Qmechanic
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Jun 23, 2011 at 12:15 comment added Qmechanic A comment to the question (v1): Note that in general (and in fact also in the specific case mentioned), a $(0,2)$ tensor is not always a product of co-vectors. Instead, it is a sum of products of co-vectors. (In the specific case the sum contains at least $4$ terms.) In fact, the same is true if the $-1$ had been a $+1$.
Jun 23, 2011 at 11:35 answer added Peter Morgan timeline score: 1
Jun 23, 2011 at 9:24 answer added Olof timeline score: 3
Jun 23, 2011 at 7:56 history asked Peter4075 CC BY-SA 3.0