Skip to main content
6 events
when toggle format what by license comment
Jan 8, 2015 at 12:42 comment added MoonKnight This is not taking into account magnetic field or the particles charge (both important factors), this formula does not look correct to me...
Jun 12, 2014 at 7:55 vote accept peterh
May 26, 2014 at 20:08 comment added Robin Ekman For circular motion $a = v^2/r = \omega^2 r$.
May 26, 2014 at 19:42 comment added diffeomorphism good question: physics.stackexchange.com/q/66839/10531
May 26, 2014 at 19:18 comment added peterh And what is the ultrarelativistic acceleration? $\omega^2r$?
May 26, 2014 at 17:04 history answered Robin Ekman CC BY-SA 3.0