2 added 28 characters in body edited May 17 '14 at 12:19 JamalS 14.7k55 gold badges3333 silver badges8787 bronze badges Yeah! That's right. Method'sThe method's fine for a time indep. H. Notindependent Hamiltonian, but not for H(t)an $$H(t)$$. Yeah! That's right. Method's fine for a time indep. H. Not for H(t). Yeah! That's right. The method's fine for a time independent Hamiltonian, but not for an $$H(t)$$. 1 answered May 17 '14 at 11:21 Yeah! That's right. Method's fine for a time indep. H. Not for H(t).