Timeline for How long does it take to optimally change position and velocity?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 13, 2014 at 3:11 | comment | added | Matthew Piziak | Thank you for your comment and question link. I've clarified the problem description. The goal is to find the path which takes the smallest amount of time. $\Delta v$ is not part of the cost function. | |
| Nov 13, 2014 at 1:44 | comment | added | fibonatic | I am not so sure if this would be the optimal solution, since you both do not give the criteria for an optimal solution and proof that those are met. To me using maximal acceleration all the time does not seem optimal. For instance when both velocities are (near) zero and you only have to cover a certain distance, then to me it would seem that applying a very small initial impulse at the start and end would suffice (when using that the total expelled $\Delta v$ would be the cost function). | |
| S Nov 12, 2014 at 23:30 | history | suggested | Matthew Piziak | CC BY-SA 3.0 |
Fixing acceleration term. See comments for confirmation of edit.
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| Nov 12, 2014 at 22:34 | review | Suggested edits | |||
| S Nov 12, 2014 at 23:30 | |||||
| May 18, 2014 at 10:42 | history | edited | nivag | CC BY-SA 3.0 |
corrected equation
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| May 18, 2014 at 10:40 | comment | added | nivag | yes you are correct. I wasn't paying attention will edit my answer | |
| May 17, 2014 at 4:19 | comment | added | Matthew Piziak | Thank you for your answer! I'm having trouble deriving the second equation. I feel that $x_f$ cannot be independent of $v_i$. I'm getting $x_f = x_i + v_i(t_1 + t_2) + \frac{1}{2}a({t_1}^2 - {t_2}^2) + at_1t_2$. | |
| May 14, 2014 at 14:51 | history | answered | nivag | CC BY-SA 3.0 |