Timeline for Using the fine structure constant to measure atomic and molecular sizes
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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May 11, 2014 at 14:35 | vote | accept | Jesse | ||
S May 11, 2014 at 12:13 | history | suggested | CommunityBot |
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May 11, 2014 at 12:11 | review | Suggested edits | |||
S May 11, 2014 at 12:13 | |||||
May 11, 2014 at 3:22 | comment | added | Jesse | yeah i fixed it. | |
May 11, 2014 at 3:22 | comment | added | LDC3 | Oh, I found it, it should be: $$\frac{r}{\lambda} = \alpha \pi Z$$ since $\alpha = \frac{ke^2}{\hbar c}$ | |
May 11, 2014 at 3:22 | history | edited | Jesse | CC BY-SA 3.0 |
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May 11, 2014 at 3:21 | comment | added | Jesse | The $m_e$ goes away, $n^2$ goes, $Z^2$ becomes Z. That leaves $\frac{\hbar}{ke^2}\alpha^2\pi Z c$ which, since $\alpha=\frac{ke^2}{\hbar c}$ means it's $\alpha \pi Z$. I think that should work, but I may have messed it. :-) | |
May 11, 2014 at 3:08 | comment | added | LDC3 | You have: $$\frac{r}{\lambda} = \frac{n^2 \hbar^2} {Zm_e k e^2}\alpha^2 \frac{\pi Z^2 m_ec}{ n^2 \hbar}$$ $$=\alpha \pi Z c$$ I must have missed a step since I don't see how you cancelled out so many terms. Where did $\frac {\hbar}{ke^2}$ go to? | |
May 11, 2014 at 2:50 | answer | added | DavePhD | timeline score: 3 | |
May 11, 2014 at 1:33 | history | edited | Jesse | CC BY-SA 3.0 |
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May 11, 2014 at 1:19 | history | asked | Jesse | CC BY-SA 3.0 |