Timeline for Energy in nuclear decays
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 11, 2014 at 6:35 | vote | accept | hb20007 | ||
| May 10, 2014 at 20:37 | comment | added | rob♦ | @hb2007 Energy (and also momentum) is conserved in all references frames. The arithmetic is easier in the rest frame of the decaying particle, but observers in all inertial reference frames will agree that total energy is conserved. In fact, in special relativity, energy and momentum make a four-vector $(E,\vec p)$ that transforms just the same way as the more familiar combinations of time and position coordinates $(t, \vec x)$. | |
| May 10, 2014 at 20:24 | comment | added | hb20007 | I see it that way because the KE of the original particle doesn't seem to be accounted for. | |
| May 10, 2014 at 20:22 | comment | added | hb20007 | I just have one more question. You said the statement is true in all known decay reactions. Is this in the special reference frame where the particle is at rest? | |
| May 10, 2014 at 18:49 | history | answered | rob♦ | CC BY-SA 3.0 |