Skip to main content
10 events
when toggle format what by license comment
Dec 5, 2020 at 19:31 comment added Christopher King @binaryfunt the velocity formula applies to reference frames in general. There do not even need to be objects involved, only reference frames.
May 31, 2014 at 2:16 comment added Brian Moths @BrianFunt No that is not a coincidence. If you have a one dimensional set of space-time events described by $dx/dt = v$ in some coordinates, and then you used primed coordinate which are boosted by a speed $u$, then the $dx'/dt'$ will be equal to the boosted speed. This is just due to the geometry of space-time. It is true independently of whether the set of events is the worldline of a particle or the wavefront of light or just an arbitrarily chosen path through spacetime.
May 30, 2014 at 21:16 comment added binaryfunt Is it just coincidental that the group velocity of light is being treated similarly to an 'object' moving at speed $v$?
May 30, 2014 at 20:58 comment added Brian Moths @BrianFunt I think I should have explained this better. Basically imagine you are standing on train tracks with the wind blowing at some speed $u$. Now you are wondering what the speed of light is. Luckily your friend is coming by on a train moving at the same speed $u$. You ask him what the speed of light is, and since he sees no wind the answer is easy: $v=c/n$. Now we have the light moving at a speed $v$ in a frame which is moving at a speed $u$ with respect to $u$, and we want to know what is the velocity in your frame. The asnwer is given by the relativistic velocity addition formula.
May 30, 2014 at 18:26 comment added binaryfunt Is there a reason why velocity addition applies to light in a moving medium?
May 2, 2014 at 20:52 comment added Brian Moths That's a good point. In reality wind is not just a uniform motion of air at a constant speed. The pressure and temperature will be non-uniform, and this will cause the index of refraction to be non-uniform. This effect on the speed of light is probably greater than the effect I talked aobut in my answer. However, it is not as easy to get a clean answer as to what the speed of light should be with these effects taken into account.
May 2, 2014 at 20:25 comment added jinawee Wouldn't turbulence and preassure be relevant for the refractive index?
May 2, 2014 at 19:15 vote accept Christopher King
May 2, 2014 at 19:15 review Suggested edits
May 2, 2014 at 19:21
May 2, 2014 at 17:44 history answered Brian Moths CC BY-SA 3.0