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Apr 29, 2014 at 2:59 comment added Blackbody Blacklight How are Q and I extensive? They are contained within the given subsystem. There is an assumption that these systems won't be divided. $\rho$ is more like an intensive chemical property, but no vector field is like that… if you want to consider any vector field as intensive, you need to decide on another model, and IUPAC at least made a decision not to do that.
Apr 28, 2014 at 18:45 comment added Jian Just like in thermophysics, $PdV$ is true,but not $VdP$.
Apr 28, 2014 at 18:42 comment added Jian $EdD$,$HdB$ can also be written as $\rho \delta \Phi$,$\vec{j}\cdot \delta \vec{A}$. But the respective $Q$,$I$ of $\rho$,$\vec{j}$ have more extensive nature than $\Phi$ and $\vec{A}$. And I wonder why can't we write $DdE,BdH ,\Phi\delta\rho,\vec{A}\cdot \delta \vec{j} $ as infinitesimal energy ?
Apr 28, 2014 at 6:00 history answered Blackbody Blacklight CC BY-SA 3.0