Number of Nuclei

Current License: CC BY-SA 3.0

10 events

when toggle format	what		by	license	comment
Apr 29, 2014 at 3:03	vote	accept	DWade64
Apr 28, 2014 at 18:35	answer	added	David Z		timeline score: 1
Apr 28, 2014 at 18:26	comment	added	David Z		@DWade64 I'd suggest editing the question to reflect that, as it's important information.
Apr 28, 2014 at 5:18	comment	added	DWade64		@DavidZ $C$ is the number of counts in a short time interval. We made like 900 different recordings. Each recording was like 4 seconds.
Apr 28, 2014 at 0:25	comment	added	David Z		Is your measurement $C$ the total number of counts accumulated since the beginning of the experiment, or is it the number of counts in a short time interval (like counts per second, for example)?
Apr 27, 2014 at 23:46	history	edited	DWade64	CC BY-SA 3.0	edited body
Apr 27, 2014 at 23:19	history	edited	dmckee --- ex-moderator kitten		edited tags
Apr 27, 2014 at 23:17	comment	added	dmckee --- ex-moderator kitten		Note also that $N = N_0 e^{-\lambda t}$ is all decays (at all angles), the decays seen by your device will actually be $N = \ell \epsilon A (N_0 e^{-\lambda t})$ where $\ell$ is live time (very nearly 1.0), $\epsilon$ is the quantum efficiency of your detector (probably also near 1), and $A$ is acceptance (a number expressing what fraction of decay gammas actually hit the detector). But all those corrections are effectively constant, so they don't affect your measured lifetime.
Apr 27, 2014 at 22:44	comment	added	rob♦		The count rate $C$ is directly proportional to the number of emitters $N$ remaining in the sample.
Apr 27, 2014 at 22:35	history	asked	DWade64	CC BY-SA 3.0