Timeline for Complex conjugate of momentum operator
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Apr 26, 2014 at 21:32 | comment | added | George G | I don't think the OP was aware of the difference between hermitian conjugation and complex conjugation, so it is better to maintain a distinction. | |
| Apr 26, 2014 at 18:31 | comment | added | Ajayu | $\hat{A}^*$ is coherent with the notation used in the question, which uses $\hat{p}^*$ as the hermitian conjugate of the impulsion operator. Althought not standard among physicist, it's the one chosen to formulate the question. | |
| Apr 26, 2014 at 4:40 | comment | added | auxsvr | @Ajayu Physicists denote complex conjugation by $\hat{A}^*$ and hermitian conjugation by $\hat{A}^\dagger$. | |
| Apr 25, 2014 at 21:58 | comment | added | Ajayu | Working on the space of infinitely differentiable functions, the distribution of the hermitian conjugation is correct in the way depicted in the question. The only problem would arrise when conjugating the multiplication of operators, in which case the only correction needed is to inverse the order of the operators in the product, like $(\hat{A}\hat{B})^*=\hat{B}^*\hat{A}^*$ | |
| Apr 25, 2014 at 19:31 | history | answered | George G | CC BY-SA 3.0 |