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Lots of grammar fixes
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edit approved Apr 12, 2014 at 12:17
CodesInChaos
edit approved Apr 12, 2014 at 12:17
CodesInChaos
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Your understanding is correct. From V=IR .$V=IR$ if voltage is The samestays the same while resistance is increased increased, the current should be decreased.

But Ifif you have heard of another equation ,

enter image description here$I = \frac{Q}{t}$

If current(I) is increased , and the charged(Q)charge $Q$ is fixed  (Number of charges areCharge is fixed if the power supply is from power cells like battery). Time will be decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fixfixed by the size of battery.

Imagine 4a four lanes road. Then , in 300 meters ahead  , there is a construction for road maintainancemaintenance for 3three lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonreveryone to get home slower.

4lanes road=Normal wire4 lanes road = Normal wire

Construction=ResistorsConstruction = Resistors

1 lane road and traffic jams=Problems cause by resistance.1 lane road and traffic jams = Problems cause by resistance.

Cars= ElectronsCars = Electrons

Home= + terminal of batteryHome= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q$Q$ but in milliampereshours not ampereseconds * hours not ampere * seconds. So 1 mAh is equal to 5/18 CulombCoulomb.

I hope you understand my explanation.

Your understanding is correct. From V=IR . if voltage is The same while resistance is increased , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead  , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.

I hope you understand my explanation

Your understanding is correct. From $V=IR$ if voltage stays the same while resistance is increased, the current should be decreased.

But if you have heard of another equation $I = \frac{Q}{t}$

If current(I) is increased and the charge $Q$ is fixed  (Charge is fixed if the power supply is from power cells like battery). Time will be decreased.

Which means that

The charges are moving faster! Because numbers of charge are fixed by the size of battery.

Imagine a four lanes road. Then in 300 meters ahead, there is a construction for road maintenance for three lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyone to get home slower.

4 lanes road = Normal wire

Construction = Resistors

1 lane road and traffic jams = Problems cause by resistance.

Cars = Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of $Q$ but in milliamperes * hours not ampere * seconds. So 1 mAh is equal to 5/18 Coulomb.

I hope you understand my explanation.

deleted 3 characters in body
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Poomrokc The 3years
Poomrokc The 3years
  • 547
  • 2
  • 5
  • 14

Your understanding is correct. From V=IR . if voltage is increasedThe same while resistance stay the sameis increased , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.

I hope you understand my explanation

Your understanding is correct. From V=IR . if voltage is increased while resistance stay the same , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.

I hope you understand my explanation

Your understanding is correct. From V=IR . if voltage is The same while resistance is increased , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.

I hope you understand my explanation

added 451 characters in body
Source Link
Poomrokc The 3years
Poomrokc The 3years
  • 547
  • 2
  • 5
  • 14

Your understanding is correct. From V=IR . if voltage is increased while resistance stay the same , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.I

I hope you understand my explanation

Your understanding is correct. From V=IR . if voltage is increased while resistance stay the same , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery. Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.I hope you understand my explanation

Your understanding is correct. From V=IR . if voltage is increased while resistance stay the same , the current should be decreased.

But If you have heard of another equation ,

enter image description here

If current(I) increased , and the charged(Q) is fixed(Number of charges are fixed if the power supply is from power cells like battery). Time will decreased.

Which means that

The charges are moving faster!! Because numbers of charge are fix by the size of battery.

Imagine 4 lanes road. Then , in 300 meters ahead , there is a construction for road maintainance for 3 lanes. Making only one lane available to pass. Cars from 4 lanes must combine into one lane, making traffic jams and cause everyonr to get home slower.

4lanes road=Normal wire

Construction=Resistors

1 lane road and traffic jams=Problems cause by resistance.

Cars= Electrons

Home= + terminal of battery

Like some phone battery have 10000mAh. Which actually is the value of Q but in milliampereshours not ampereseconds. So 1 mAh is equal to 5/18 Culomb.

I hope you understand my explanation

added 24 characters in body
Source Link
Poomrokc The 3years
Poomrokc The 3years
  • 547
  • 2
  • 5
  • 14
Source Link
Poomrokc The 3years
Poomrokc The 3years
  • 547
  • 2
  • 5
  • 14