Timeline for Orbital motion with varying radius
Current License: CC BY-SA 3.0
3 events
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Apr 6, 2014 at 16:26 | comment | added | Tadeus Prastowo | Sorry, I wrote the first three terms incorrectly, the equation should be the following one (can I really conclude that $F_\text{tangential} = m\omega\frac{dR}{dt}$)? $F_\text{tangential} = m a_\text{tangential} = m R \alpha = m R \frac{d\omega}{dt} = m R \frac{\omega_f-\omega_i}{dt} = \frac{m R \omega_f - m R \omega_i}{dt} = \frac{m R_f \omega - m R_i \omega}{dt} = m \omega \frac{R_f - R_i}{dt} = m \omega \frac{dR}{dt}$ | |
Apr 6, 2014 at 16:16 | comment | added | Tadeus Prastowo | For the motion depicted here !A circular motion with a varying radius, I argue that the relationships given about circular motion in basic Physics textbooks cannot describe the transition from the circle of radius R' to the circle of radius R and then back again. That is, can I say the following? $F_\text{tangential} = m a_\text{tangential} = m \frac{dv}{dt} = m \frac{R d\omega}{dt} = m R \frac{\omega_f-\omega_i}{dt} = \frac{m R \omega_f - m R \omega_i}{dt} = \frac{m R_f \omega - m R_i \omega}{dt} = m \omega \frac{R_f - R_i}{dt} = m \omega \frac{dR}{dt}$ | |
Apr 6, 2014 at 13:47 | history | answered | fibonatic | CC BY-SA 3.0 |