Timeline for Speed of light that is traveling away from the observer
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Mar 8, 2015 at 14:32 | vote | accept | CommunityBot | ||
Apr 15, 2014 at 14:53 | answer | added | bright magus | timeline score: 1 | |
Mar 30, 2014 at 11:19 | comment | added | Henry | You have to consider the observer's "reference frame", not her point of view | |
Mar 30, 2014 at 10:44 | history | edited | user43187 | CC BY-SA 3.0 |
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Mar 29, 2014 at 18:38 | comment | added | user43187 | Thanks Nick, I think your comment is closest to the answer after all. As I understand it now, the light is still going at the speed c for the observer, he is just not able see that direction. What helped me to understand was the idea of something moving at the speed (v,0,0) in some frame of reference (coordinate system). Then consider observer standing in the origin of such coordinate system. He wouldn't see the actual movement, but that wouldnt change the fact that the object is moving at the speed of v relative to his frame of reference. | |
Mar 28, 2014 at 12:36 | vote | accept | CommunityBot | ||
Mar 29, 2014 at 18:09 | |||||
Mar 24, 2014 at 21:05 | answer | added | Moonraker | timeline score: 0 | |
Mar 24, 2014 at 21:05 | review | First posts | |||
Mar 24, 2014 at 21:06 | |||||
Mar 24, 2014 at 21:04 | comment | added | Nick | My guess is that in your reasoning you "projected out" the dimension in which light was moving. How do you measure the speed of the "dot" if don't have any clue what distance it moves in a given time ? | |
Mar 24, 2014 at 20:58 | comment | added | Řídící | You only see light when it actually hits your eye. | |
Mar 24, 2014 at 20:53 | history | edited | user43187 | CC BY-SA 3.0 |
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Mar 24, 2014 at 20:48 | history | asked | user43187 | CC BY-SA 3.0 |