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Feb 20, 2021 at 17:06 comment added Andrew Steane Quasistatic == "Passing through a series of equilibrium states". The frictionless pendulum is not quasistatic by that definition, but its state at any moment only differs from an equilibrium state by a shift in phase-space. This suggests one might see it as an intermediate case, not quasistatic by the ordinary use of the term and yet quasistatic in all ways that matter for the purposes of entropy calculations. I mean the forces on it, and its response, move it through a sequence of states, each of which is an equilibrium state up to a global shift of all microstates together.
Mar 15, 2014 at 6:54 history bounty ended CommunityBot
Mar 14, 2014 at 8:04 vote accept Gerard
Mar 9, 2014 at 3:26 history edited N. Virgo CC BY-SA 3.0
corrected the calculation section. (I now realise it would be better to do the full calculation without the approximations - if I get a chance I'll change it - but I think this is ok.)
Mar 8, 2014 at 7:38 vote accept Gerard
Mar 14, 2014 at 8:04
Mar 8, 2014 at 7:32 comment added N. Virgo @Gerard yes, I think that is by far the best way to think about it.
Mar 8, 2014 at 7:30 comment added Gerard So, a reversible process isn't necessarily quasi-static. In essence, then, a reversible process is simply that can be brought back to its initial state, with no change anywhere in the Universe, right? In other words, with no entropy change.
Mar 8, 2014 at 6:28 history edited N. Virgo CC BY-SA 3.0
answered the last part of the question.
Mar 8, 2014 at 6:23 history answered N. Virgo CC BY-SA 3.0